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TS3V555ID-TS3V555IDT-TS3V555IN
3V LOW POWER SINGLE CMOS TIMER
TS3V555
3V LOW POWER SINGLE TIMERSOctober 1997 DEDICATED TO 3.3V OR BATTERY SUPPLY
(Specified at 3V and 5V). VERY LOW POWER CONSUMPTION :
90μA at VCC = 3V. WIDE SINGLE SUPPLY RANGE :
+2.7V to +16V. HIGH OUTPUT CURRENT CAPABILITY. SUPPLY CURRENT SPIKES REDUCED
DURING OUTPUT TRANSITIONS . HIGH INPUT IMPEDANCE : 10
12 Ω. PIN-TO-PIN AND FUNCTIONALLY COMPAT-
IBLE WITH BIPOLAR NE555 AND CMOS
TS555. OUTPUT COMPATIBLE WITH TTL,CMOS
AND LOGIC MOS
DESCRIPTIONThe TS3V555 with its low consumption (90μA at
VCC = 3V) is a single CMOS timer dedicated to 3.3V
or battery supply (specified at 3V and 5V) offering
also a high frequency (f(max) 2MHz at VCC = 3V and
2.7 MHz at VCC = 5V). Thus, either in monostable
or astable mode, timing remains very accurate.
Timing capacitors can also be minimized due to
high input impedance (1012 Ω).
PIN CONNECTIONS (top view)
ORDER CODES1/8
FUNCTION TABLE
LOW � Level Voltage ≤ Min voltage specified
HIGH � Level Voltage ≥ Max voltage specified
� Irrelevant
ABSOLUTE MAXIMUM RATINGS
THERMAL CHARACTERISTICS
BLOCK DIAGRAM
OPERATING CONDITIONS
TS3V5552/8
ELECTRICAL CHARACTERISTICSVCC = +3V , Tamb = +25o C , Reset to VCC (unless otherwise specified)
STATIC
DYNAMIC
Note : 1. See Figure 2
2. See Figure 4
TS3V5553/8
ELECTRICAL CHARACTERISTICSVCC = +5V , Tamb = +25o C , Reset to VCC (unless otherwise specified)
STATIC
DYNAMIC
Note : 1. See Figure 2
2. See Figure 4
TS3V5554/8
APPLICATION INFORMATIONMONOSTABLE OPERATION
In the monostable mode,the timer functions as a
one-shot. Referring to figure 2 the external capaci-
tor is initially held discharged by a transistor inside
the timer.
Figure 2CAPACITOR VOLTAGE = 2.0V/divΩ μ
t = 0.1 ms / div
R = 9.1k , C = 0.01 F , R = 1.0kL
Figure 3
TYPICAL CHARACTERISTICSSUPPLY VOLTAGE, V (V)
T, I
0 4 8 12 16
Figure 1 : Supply Current (each timer)
versus supply voltage.
The circuit triggers on a negative-going input signal
when the level reaches 1/3 VCC. Once triggered,the
circuit remains in this state until the set time has
elapsed,even if it is triggered again during this
interval. The duration of the output HIGH state is
given by t = 1.1 R x C.
Notice that since the charge rate and the threshold
level of the comparator are both directly propor-
tional to supply voltage, the timing interval is inde-
pendent of supply. Applying a negative pulse
simultaneously to the Reset terminal (pin 4) and the
Trigger terminal (pin 2) during the timing cycle
discharges the external capacitor and causes the
cycle to start over. The timing cycle now starts on
the positive edge of the reset pulse. During the time
the reset pulse is applied, the output is driven to its
LOW state.
When a negative trigger pulse is applied to pin 2,
the flip-flop is set, releasing the short circuit across
the external capacitor and driving the output HIGH.
The voltage across the capacitor increases expo-
nentially with the time constant τ = R x C.
When the voltage across the capacitor equals 2/3
VCC, the comparator resets the flip-flop which then
discharges the capacitor rapidly and drives the
output to its LOW state.
Figure 3 shows the actual waveforms generated in
this mode of operation.
When Reset is not used, it should be tied high to
avoid any possible or false triggering.
TS3V5555/8
Figure 4Ω μ
t = 0.5 ms / div
CAPACITOR VOLTAGE = 1.0V/div R = R = 4.8 k , C = 0.1 F , R = 1.0kAB
Figure 5ASTABLE OPERATION
When the circuit is connected as shown in figure 4
(pin 2 and 6 connected) it triggers itself and free
runs as a multivibrator. The external capacitor
charges through RA and RB and discharges
through RB only. Thus the duty cycle may be pre-
cisely set by the ratio of these two resistors.
In the astable mode of operation, C charges and
discharges between 1/3 VCC and 2/3 VCC. As in the
triggered mode, the charge and discharge times
and therefore frequency, are independent of the
supply voltage.
Figure 5 shows actual waveforms generated in this
mode of operation.
The charge time (output HIGH) is given by :
t1 = 0.693 (RA + RB) C
and the discharge time (output LOW) by :
t2 = 0.693 (RB) C
Thus the total period T is given by :
T = t1 + t2 = 0.693 (RA + 2RB) C
The frequency of oscillation is then :
f = 1 = 1.44
(RA + 2RB) C
The duty cycle is given by : D = RB
RA + 2RB
TS3V5556/8
